Two short bar magnets of magnetic moments $m$ each are arranged at the opposite corners of a square of side $d$ such that their centres coincide with the corners and their axes are parallel. If the like poles are in the same direction, the magnetic induction at any of the other corners of the square is

  • A

    $\frac{{{\mu _0}}}{{4\pi }}\frac{m}{{{d^3}}}$

  • B

    $\frac{{{\mu _0}}}{{4\pi }}\frac{{2m}}{{{d^3}}}$

  • C

    $\frac{{{\mu _0}}}{{4\pi }}\frac{m}{{2{d^3}}}$

  • D

    $\frac{{{\mu _0}}}{{4\pi }}\frac{{{m^3}}}{{2{d^3}}}$

Similar Questions

The correct relation is

$B_H$ $=$ Horizontal component of earth's magnetic field;  $B_V$ $=$ Vertical component of earth's magnetic field and $B  =$  Total intensity of earth's magnetic field

Due to the earth's magnetic field, charged cosmic ray particles

  • [AIPMT 1997]

Explain geographic meridian and magnetic meridian.

A compass needle whose magnetic moment is $60 \,amp × m^2$ pointing geographical north at a certain place, where the horizontal component of earth's magnetic field is $40\, \mu Wb/m^2$, experiences a torque $1.2 \times {10^{ - 3}}\,N \times m.$ What is the declination at this place......$^o$

A dip circle is adjusted so that its needle moves freely in the magnetic meridian. In this position, the angle of dip is $40°$. Now the dip circle is rotated so that the plane in which the needle moves makes an angle of $30°$ with the magnetic meridian. In this position the needle will dip by an angle