Two rain drops falling through air have radii in the ratio $1: 2$. They will have terminal velocity in the ratio

Two raindrops reach the earth with different terminal velocities having the ratio $9: 4$. The ratio of their volumes is

The velocity of a small ball of mass $0.3 \, g$ and density $8 \, g/cc$ when dropped in a container filled with glycerine becomes constant after some time. If the density of glycerine is $1.3 \, g/cc$,then the value of the viscous force acting on the ball will be $x \times 10^{-4} \, N$. The value of $x$ is [use $g = 10 \, m/s^2$]. (in $.125$)

The graph between terminal velocity $(v_t)$ (along $y$-axis) and the square of the radius $(r^2)$ (along $x$-axis) of a spherical body of density $\rho$ falling through a fluid of density $\sigma$ is:

$A$ lead sphere of mass $m$ falls in a viscous liquid with terminal velocity $V_0$. Another lead sphere of mass $8m$ but of the same material will fall through the same liquid with terminal velocity:

Two drops of equal radius are falling through air with a steady velocity of $5\,cm/s$. If the two drops coalesce,then its terminal velocity will be