Two rails are represented by the equations $x+2y-4=0$ and $2x+4y-12=0$. Represent this situation geometrically.

(N/A) To represent the equations geometrically,we find two solutions for each equation.
For the equation $x+2y-4=0$:

$x$	$0$	$4$
$y = \frac{4-x}{2}$	$2$	$0$

We plot the points $R(0, 2)$ and $S(4, 0)$ to get the line representing $x+2y-4=0$.
For the equation $2x+4y-12=0$:

$x$	$0$	$6$
$y = \frac{12-2x}{4}$	$3$	$0$

We plot the points $P(0, 3)$ and $Q(6, 0)$ to get the line representing $2x+4y-12=0$.
Observing the graph,we see that the two lines do not intersect anywhere,which means they are parallel to each other.