Two radioactive substances $X$ and $Y$ originally have $N_{1}$ and $N_{2}$ nuclei respectively. The half-life of $X$ is half of the half-life of $Y$. After three half-lives of $Y$,the number of nuclei of both are equal. The ratio $\frac{N_{1}}{N_{2}}$ will be equal to:

  • A
    $\frac{1}{8}$
  • B
    $\frac{3}{1}$
  • C
    $\frac{8}{1}$
  • D
    $\frac{1}{3}$

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