Two racing cars of masses m_1 and m_2 are mov | vedclass

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Question

(A) The angular speed $\omega$ of an object moving in a circle is defined as the angle covered per unit time. For a complete circle,the angle covered

Vedclass · Accepted Answer

$1 : 1$

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(A) The angular speed $\omega$ of an object moving in a circle is defined as the angle covered per unit time. For a complete circle,the angle covered is $2\pi$ radians. If the time taken to complete one circle is $t$,then the angular speed is given by $\omega = \frac{2\pi}{t}$. Since both cars complete a circle in the same time $t$,their angular speeds are: $\omega_1 = \frac{2\pi}{t}$ and $\omega_2 = \frac{2\pi}{t}$. Therefore,the ratio of the angular speeds is $\frac{\omega_1}{\omega_2} = \frac{2\pi/t}{2\pi/t} = 1 : 1$.

Two racing cars of masses $m_1$ and $m_2$ are moving in circles of radii $r_1$ and $r_2$ respectively. Their speeds are such that each makes a complete circle in the same time $t$. The ratio of the angular speeds of the first to the second car is

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