Two polarizers are placed such that the angle between their transmission axes is $60^o$. If unpolarised light of intensity $I_0$ is incident on the first polarizer,then the transmitted intensity from the second polarizer will be

  • A
    $\frac{I_0}{2}$
  • B
    $\frac{I_0}{4}$
  • C
    $\frac{I_0}{6}$
  • D
    $\frac{I_0}{8}$

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Similar Questions

Unpolarised light from air is incident on the surface of a transparent medium of refractive index $1.414$ such that the reflected light is completely polarised. Match the angles given in List-$I$ with the corresponding values given in List-$II$.
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$B$. Angle of refraction$(ii)$ $\sin^{-1} \left(\sqrt{\frac{2}{3}}\right) - \sin^{-1} \left(\frac{1}{\sqrt{3}}\right)$
$C$. Angle between incident and completely polarised light$(iii)$ $\sin^{-1} \left(\frac{1}{\sqrt{3}}\right)$
$D$. Angle of deviation of the incident ray$(iv)$ $\cos^{-1} \left(\frac{1}{\sqrt{3}}\right)$

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