Two players $A$ and $B$ alternatively toss $3$ coins simultaneously. The player who gets $2$ heads and $1$ tail first,wins the game. If the game continues until someone wins and if $A$ begins the game,the probability that $B$ wins the game is

  • A
    $\frac{24}{39}$
  • B
    $\frac{4}{7}$
  • C
    $\frac{15}{39}$
  • D
    $\frac{3}{7}$

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