Two pipes can separately fill a tank in 20 hr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The rate of filling by both pipes in $1$ $hr$ is $\frac{1}{20} + \frac{1}{30} = \frac{3+2}{60} = \frac{5}{60} = \frac{1}{12}$ of the tank.Time tak

Vedclass · Accepted Answer

$16$

Vedclass · Answer

(C) The rate of filling by both pipes in $1$ $hr$ is $\frac{1}{20} + \frac{1}{30} = \frac{3+2}{60} = \frac{5}{60} = \frac{1}{12}$ of the tank.Time taken to fill $\frac{1}{3}$ of the tank is $\frac{1/3}{1/12} = 4$ $hrs$.After the tank is $\frac{1}{3}$ full,a leak develops. The leak removes $\frac{1}{3}$ of the water supplied by both pipes per hour.Net rate of filling after the leak = $(	ext{Rate of both pipes}) - (	ext{Leakage rate}) = \frac{1}{12} - (\frac{1}{3} 	imes \frac{1}{12}) = \frac{1}{12} - \frac{1}{36} = \frac{3-1}{36} = \frac{2}{36} = \frac{1}{18}$ of the tank per hour.The remaining part of the tank to be filled is $1 - \frac{1}{3} = \frac{2}{3}$.Time taken to fill the remaining $\frac{2}{3}$ part = $\frac{2/3}{1/18} = \frac{2}{3} 	imes 18 = 12$ $hrs$.Total time taken = $4$ $hrs + 12$ $hrs = 16$ $hrs$.

Similar Questions

One fill pipe $A$ is $3$ times faster than second fill pipe $B$ and takes $32$ minutes less than the fill pipe $B$. When will the cistern be full if both the pipes are opened together?

Three taps $A, B$ and $C$ fill a tank in $20$ min,$15$ min and $12$ min,respectively. If all the taps are opened simultaneously,how long will they take to fill $40 \%$ of the tank (in $min$)?

Two pipes $A$ and $B$ can fill a cistern in $24$ $minutes$ and $30$ $minutes$,respectively. There is also an outlet $C$. If all the three pipes are opened together,the cistern is full in $20$ $minutes$. How much time (in $minutes$) will be taken by outlet $C$ to empty the full cistern?

Vedclass Test Series

Exam Paper Generator

Online Exam Module