Two persons of mass m_1 and m_2 are standing | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The system consists of the trolley and the two persons. Since there is no external horizontal force acting on the system,the net external horizont

Vedclass · Accepted Answer

None of these

Vedclass · Answer

(D) The system consists of the trolley and the two persons. Since there is no external horizontal force acting on the system,the net external horizontal force is zero $(F_{ext, x} = 0)$.According to the law of conservation of linear momentum,the velocity of the centre of mass of the system remains constant. Since the system was initially at rest,the velocity of the centre of mass remains zero.Let the horizontal velocity of the person of mass $m_1$ be $v$ towards the left and the person of mass $m_2$ be $v$ towards the right. Let the velocity of the trolley be $V$ towards the right.Applying the conservation of linear momentum in the horizontal direction:$m_1(-v) + m_2(v) + MV = 0$$MV = m_1v - m_2v$$V = \frac{(m_1 - m_2)v}{M}$If $m_1 > m_2$,then $V > 0$,meaning the trolley moves towards the right (towards end $B$).If $m_2 > m_1$,then $V Thus,the trolley moves towards the end where the person with the lighter mass was standing,which is equivalent to saying it moves away from the heavier mass. Therefore,none of the given options are correct.

Two persons of mass $m_1$ and $m_2$ are standing at the two ends $A$ and $B$ respectively,of a trolley of mass $M$ as shown. When both the persons jump simultaneously with the same speed,then:

Similar Questions

$A$ monkey of mass $m$ is at rest on a light rope attached to a balloon of mass $M$ in mid-air. If the monkey climbs up the rope and reaches the top of the rope,what is the distance covered by the balloon? (The total length of the rope is $L$)

Two spheres of masses $2M$ and $M$ are initially at rest at a distance $R$ apart. Due to mutual force of attraction,they approach each other. When they are at a separation $R/2$,the acceleration of the centre of mass of the system would be ....... $m/s^2$.

Write the expression for the centre of mass of a system of $n$ particles and derive the formula for the force acting on its centre of mass.

Internal forces acting within a system of particles can alter

Vedclass Test Series

Exam Paper Generator

Online Exam Module