Two persons $A$ and $B$ take turns in throwing a pair of dice. The first person to throw a sum of $9$ with both dice will win the game. If $A$ throws first,then the probability that $B$ wins the game is:

  • A
    $\frac{9}{17}$
  • B
    $\frac{8}{17}$
  • C
    $\frac{8}{9}$
  • D
    $\frac{1}{9}$

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