Two packs of 52 cards are shuffled together. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) There are $52$ distinct types of cards (suit and denomination combination). Since there are two packs,each of these $52$ types appears twice.To se

Vedclass · Accepted Answer

$^{52}C_{26} \cdot 2^{26}$

Vedclass · Answer

(A) There are $52$ distinct types of cards (suit and denomination combination). Since there are two packs,each of these $52$ types appears twice.To select $26$ cards such that no two cards have the same suit and same denomination,we must first choose $26$ distinct types out of the $52$ available types. This can be done in $^{52}C_{26}$ ways.For each of the $26$ chosen cards,we have $2$ choices (either from the first pack or the second pack).Since there are $26$ such cards,the total number of ways is $^{52}C_{26} 	imes 2^{26}$.

Two packs of $52$ cards are shuffled together. The number of ways in which a man can be dealt $26$ cards so that he does not get two cards of the same suit and same denomination is

Similar Questions

$A$ dictionary is printed consisting of $7$-letter words only that can be formed using the letters of the word $CRICKET$. If the words are arranged in alphabetical order,as in an ordinary dictionary,then the number of words before the word $CRICKET$ is:

There are $10$ persons named $A, B, \dots, J$. We have the capacity to accommodate only $5$. In how many ways can we arrange them in a line if $A$ must be included and $G$ and $H$ must not be included in the team of $5$?

There are $n$ straight lines in a plane,no two of which are parallel and no three pass through the same point. Their points of intersection are joined. Then the number of fresh lines thus obtained is

The number of ways in which $9$ persons can be divided into three equal groups is

If $n$ is a factor of $72$,such that $xy = n$,then the number of ordered pairs $(x, y)$ is: (where $x, y \in N$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module