Two open organ pipes of length $60 \,cm$ and $90 \,cm$ resonate at $6^{\text{th}}$ and $5^{\text{th}}$ harmonics respectively. The difference of frequencies for the given modes is . . . . . $Hz$.
(Velocity of sound in air $= 333 \,m/s$)

The fundamental frequency of a closed organ pipe is equal to the first overtone frequency of an open organ pipe. If the length of the open pipe is $60 \,cm$, the length of the closed pipe will be: (in $\,cm$)

$A$ whistle whose air column is open at both ends has a fundamental frequency of $5100 \ Hz$. If the speed of sound in air is $340 \ ms^{-1}$,the length of the whistle,in $cm$,is

Two open organ pipes of length $50 \, cm$ and $50.5 \, cm$ produce $3$ beats per second. The velocity of sound is ..... $m/s$.

$A$ closed organ pipe of length $L$ and an open organ pipe contain gases of densities $\rho_1$ and $\rho_2$ respectively. The compressibility of the gases is equal in both the pipes. If the frequencies of their first overtones are the same,then the length of the open organ pipe is:

$A$ source of sound placed at the open end of a resonance column sends an acoustic wave of pressure amplitude ${\rho _0}$ inside the tube. If the atmospheric pressure is ${\rho _A},$ then the ratio of maximum and minimum pressure at the closed end of the tube will be