Two objects of masses 200 text{ g} and 500 te | vedclass

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(C) Given masses are $m_1 = 200 	ext{ g}$ and $m_2 = 500 	ext{ g}$.Velocities are $v_1 = 10 \hat{i} 	ext{ m/s}$ and $v_2 = (3 \hat{i} + 5 \hat{j})

Vedclass · Accepted Answer

$5 \hat{i} + \frac{25}{7} \hat{j}$

Vedclass · Answer

(C) Given masses are $m_1 = 200 	ext{ g}$ and $m_2 = 500 	ext{ g}$.Velocities are $v_1 = 10 \hat{i} 	ext{ m/s}$ and $v_2 = (3 \hat{i} + 5 \hat{j}) 	ext{ m/s}$.The velocity of the centre of mass $(v_{CM})$ is given by the formula:$v_{CM} = \frac{m_1 v_1 + m_2 v_2}{m_1 + m_2}$Substituting the values:$v_{CM} = \frac{200(10 \hat{i}) + 500(3 \hat{i} + 5 \hat{j})}{200 + 500}$$v_{CM} = \frac{2000 \hat{i} + 1500 \hat{i} + 2500 \hat{j}}{700}$$v_{CM} = \frac{3500 \hat{i} + 2500 \hat{j}}{700}$$v_{CM} = 5 \hat{i} + \frac{25}{7} \hat{j} 	ext{ m/s}$.

Two objects of masses $200 \text{ g}$ and $500 \text{ g}$ possess velocities $10 \hat{i} \text{ m/s}$ and $(3 \hat{i} + 5 \hat{j}) \text{ m/s}$ respectively. The velocity of their centre of mass in $\text{m/s}$ is:

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