Two numbers are respectively 12 frac{1}{2} % | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the third number be $100$.Since the first number is $12 \frac{1}{2} \%$ more than the third number,the first number $= 100 + 12.5 = 112.5$.Sin

Vedclass · Accepted Answer

$90$

Vedclass · Answer

(D) Let the third number be $100$.Since the first number is $12 \frac{1}{2} \%$ more than the third number,the first number $= 100 + 12.5 = 112.5$.Since the second number is $25 \%$ more than the third number,the second number $= 100 + 25 = 125$.We need to find the first number as a percentage of the second number.Required percentage $= (\frac{112.5}{125}) 	imes 100$.$= 0.9 	imes 100 = 90 \%$.

Two numbers are respectively $12 \frac{1}{2} \%$ and $25 \%$ more than a third number. The first number as a percentage of the second number is

Similar Questions

The price of onions has been increased by $50 \%$. In order to keep the expenditure on onions the same,the percentage of reduction in consumption has to be:

If $50 \%$ of $(x-y) = 30 \%$ of $(x+y)$,then what percent of $x$ is $y$?

$A$ batsman scored $110$ runs which included $3$ boundaries and $8$ sixes. What percent of his total score did he make by running between the wickets?

In expressing a length $81.472 \, km$ as nearly as possible with three significant digits,find the percentage error?

If the price of a book is first decreased by $25 \%$ and then increased by $20 \%,$ then the net change in the price will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module