Two numbers are less than a third number by 3 | vedclass

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(D) Let the third number be $100$.The first number is $30 \%$ less than $100$,so it is $100 - 30 = 70$.The second number is $37 \%$ less than $100$,so

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$10$

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(D) Let the third number be $100$.The first number is $30 \%$ less than $100$,so it is $100 - 30 = 70$.The second number is $37 \%$ less than $100$,so it is $100 - 37 = 63$.We need to find how much percent the second number $(63)$ is less than the first number $(70)$.Difference $= 70 - 63 = 7$.Required percentage $= \left( \frac{	ext{Difference}}{	ext{First number}} ight) 	imes 100 = \left( \frac{7}{70} ight) 	imes 100$.$= 0.1 	imes 100 = 10 \%$.

Two numbers are less than a third number by $30 \%$ and $37 \%$ respectively. How much per cent is the second number less than the first (in $\%$)?

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