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(A) Let the spring force be $F_s$. The $10\,kg$ mass is pulled by the spring force $F_s$ towards the right.Using Newton's second law for the $10\,kg$

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(A) Let the spring force be $F_s$. The $10\,kg$ mass is pulled by the spring force $F_s$ towards the right.Using Newton's second law for the $10\,kg$ mass: $F_s = m_1 a_1 = 10\,kg 	imes 12\,m/s^2 = 120\,N$.Now,consider the $20\,kg$ mass. The external force of $200\,N$ acts towards the right,and the spring force $F_s$ acts towards the left (Newton's third law).Using Newton's second law for the $20\,kg$ mass: $F_{net} = F_{ext} - F_s = m_2 a_2$.$200\,N - 120\,N = 20\,kg 	imes a_2$.$80\,N = 20\,kg 	imes a_2$.$a_2 = \frac{80}{20} = 4\,m/s^2$ towards the right.

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