Two masses ${m_1}$ and ${m_2}$ are suspended together by a massless spring of constant k. When the masses are in equilibrium, ${m_1}$ is removed without disturbing the system. Then the angular frequency of oscillation of ${m_2}$ is
$\sqrt {\frac{k}{{{m_1}}}} $
$\sqrt {\frac{k}{{{m_2}}}} $
$\sqrt {\frac{k}{{{m_1} + {m_2}}}} $
$\sqrt {\frac{k}{{{m_1}{m_2}}}} $
What is condition for a body suspended at the end of a spring having simple harmonic oscillation ?
A $2\, Kg$ block moving with $10\, m/s$ strikes a spring of constant $\pi ^2 N/m$ attached to $2\, Kg$ block at rest kept on a smooth floor, the velocity of the rear $2\, kg$ block after it separates from the spring will be ..... $m/s$
Two springs having spring constant $k_1$ and $k_2$ is connected in series, its resultant spring constant will be $2\,unit$. Now if they connected in parallel its resultant spring constant will be $9\,unit$, then find the value of $k_1$ and $k_2$.
A spring of force constant $k$ is cut into two pieces such that one piece is double the length of the other. Then the long piece will have a force constant of
In arrangement given in figure, if the block of mass m is displaced, the frequency is given by