(C) The magnetic force per unit length between two parallel wires carrying currents $I_1$ and $I_2$ separated by distance $d$ is given by $f = \frac{\

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(C) The magnetic force per unit length between two parallel wires carrying currents $I_1$ and $I_2$ separated by distance $d$ is given by $f = \frac{\mu_0 I_1 I_2}{2 \pi d}$.For length $L$,the force is $F = \frac{\mu_0 I^2 L}{2 \pi d}$.In the new condition,the distance $d' = \frac{d}{2}$ and the currents $I' = 2I$.The new force $F_2$ is given by $F_2 = \frac{\mu_0 (2I)(2I) L}{2 \pi (d/2)}$.Simplifying this,we get $F_2 = \frac{\mu_0 (4I^2) L}{2 \pi (d/2)} = 8 \times \left( \frac{\mu_0 I^2 L}{2 \pi d} \right)$.Therefore,$F_2 = 8F$.

Class 12 Physics Moving Charges and Magnetism Force on a Current Carrying Conductor

Medium

Two long straight wires $A$ and $B$ carrying equal current $I$ were kept parallel to each other at distance $d$ apart. The magnitude of the magnetic force experienced by length $L$ of wire $A$ is $F$. If the distance between the wires is halved and the currents are doubled,the force $F_2$ on length $L$ of wire $A$ will be:

MHT CET 2025 All MHT CET

A
$2 F$
B
$F$
C
$8 F$
D
$4 F$

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Class 12

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Moving Charges and Magnetism

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Force on a Current Carrying Conductor

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Three long straight wires carrying current are arranged mutually parallel as shown in the figure. The force experienced by $15 \ cm$ length of wire $Q$ is . . . . . . . $(\mu_0 = 4 \pi \times 10^{-7} \ T \cdot m/A)$

DifficultJEE MAIN 2026

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$A$ square of side $2.0\,m$ is placed in a uniform magnetic field $B = 2.0\,T$ in a direction perpendicular to the plane of the square inwards. Equal current,$i = 3.0\,A$ is flowing in the direction shown in the figure. Find the magnitude of the magnetic force on the loop.

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$A$ conductor in the form of a right angle $ABC$ with $AB = 3\, cm$ and $BC = 4\, cm$ carries a current of $10\, A$. There is a uniform magnetic field of $5\, T$ perpendicular to the plane of the conductor. The force on the conductor will be......$N$

Medium

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$A$ horizontal semi-circular wire of radius $r$ is connected to a battery through two similar springs $X$ and $Y$. The battery sends a current $I$ through the wire. $A$ uniform magnetic field $B$ is applied perpendicular to the plane of the wire,as shown in the figure. What is the force acting on each spring?

MediumWBJEE 2022

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In the given figure,the magnetic force on the wire $ABC$ will be $(B = 2 \, T, I = 2 \, A)$.

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Three long straight wires carrying current are arranged mutually parallel as shown in the figure. The force experienced by $15 \ cm$ length of wire $Q$ is . . . . . . . $(\mu_0 = 4 \pi \times 10^{-7} \ T \cdot m/A)$

$A$ square of side $2.0\,m$ is placed in a uniform magnetic field $B = 2.0\,T$ in a direction perpendicular to the plane of the square inwards. Equal current,$i = 3.0\,A$ is flowing in the direction shown in the figure. Find the magnitude of the magnetic force on the loop.

$A$ conductor in the form of a right angle $ABC$ with $AB = 3\, cm$ and $BC = 4\, cm$ carries a current of $10\, A$. There is a uniform magnetic field of $5\, T$ perpendicular to the plane of the conductor. The force on the conductor will be......$N$

In the given figure,the magnetic force on the wire $ABC$ will be $(B = 2 \, T, I = 2 \, A)$.

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