(C) The ratio is given by $K = \frac{\cos \theta_{A}}{\cos \theta_{B}}$.For $K$ to be negative,$\cos \theta_{A}$ and $\cos \theta_{B}$ must have oppos

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$K$ is negative,then liquid $A$ has concave meniscus and liquid $B$ has convex meniscus.

(C) The ratio is given by $K = \frac{\cos \theta_{A}}{\cos \theta_{B}}$.For $K$ to be negative,$\cos \theta_{A}$ and $\cos \theta_{B}$ must have opposite signs.If $\theta 0$ (concave meniscus).If $\theta > 90^{\circ}$,$\cos \theta Therefore,if $K 90^{\circ})$.

Class 11 Physics Fluid Mechanics and Surface Tension Angle of Contact

Difficult

Two liquids $A$ and $B$ have $\theta_{A}$ and $\theta_{B}$ as contact angles in a capillary tube. If $K = \cos \theta_{A} / \cos \theta_{B}$,then identify the correct statement:

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A
$K$ is negative,then liquid $A$ and liquid $B$ have convex meniscus.
B
$K$ is negative,then liquid $A$ and liquid $B$ have concave meniscus.
C
$K$ is negative,then liquid $A$ has concave meniscus and liquid $B$ has convex meniscus.
D
$K$ is zero,then liquid $A$ has convex meniscus and liquid $B$ has concave meniscus.