Two large vertical and parallel metal plates | vedclass

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Question

$mg = qE $

$1.67 	imes 10^{-27} 	imes 10=1.6 	imes 10^{-19} 	imes \frac{ X }{0.01} $

$X=\frac{1.67}{1.6} 	imes 10^{-9} V $

$X=1 	imes 1

Vedclass · Accepted Answer

$1 	imes 10^{-9} \ V$

Vedclass · Answer

$mg = qE $

$1.67 	imes 10^{-27} 	imes 10=1.6 	imes 10^{-19} 	imes \frac{ X }{0.01} $

$X=\frac{1.67}{1.6} 	imes 10^{-9} V $

$X=1 	imes 10^{-9} V$

Two large vertical and parallel metal plates having a separation of $1 \ cm$ are connected to a $DC$ voltage source of potential difference $X$. A proton is released at rest midway between the two plates. It is found to move at $45^{\circ}$ to the vertical $JUST$ after release. Then $X$ is nearly

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