Two identical spheres are placed in contact w | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(c) $F = G\frac{{M 	imes M}}{{{R^2}}} = \frac{{G\, 	imes \,{{\left( {\frac{4}{3}\pi {R^3}ho } ight)}^2}}}{{{{(2R)}^2}}} \Rightarrow F \propto \f

Vedclass · Accepted Answer

${R^4}$

Vedclass · Answer

(c) $F = G\frac{{M 	imes M}}{{{R^2}}} = \frac{{G\, 	imes \,{{\left( {\frac{4}{3}\pi {R^3}ho } ight)}^2}}}{{{{(2R)}^2}}} \Rightarrow F \propto \frac{{{R^6}}}{{{R^2}}} \propto {R^4}$

Two identical spheres are placed in contact with each other. The force of gravitation between the spheres will be proportional to ($R =$ radius of each sphere)

Similar Questions

A planet orbits the sun in an elliptical path as shown in the figure. Let $v_P$ and $v_A$ be speed of the planet when at perihelion and aphelion respectively. Which of the following relations is correct ?

According to Kepler’s law the time period of a satellite varies with its radius as

Starting from the centre of the earth having radius $R,$ the variation of $g$ (acceleration due to gravity) is shown by

A satellite can be in a geostationary orbit around a planet at a distance $r$ from the centre of the planet. If the angular velocity of the planet about its axis doubles, a satellite can now be in a geostationary orbit around the planet if its distance from the centre of the planet is

If the distance between the centres of Earth and Moon is $D$ and mass of Earth is $81\, times$ that of Moon. At what distance from the centre of Earth gravitational field will be zero?