Two identical solid balls,one of ivory and the other of wet-clay,are dropped from the same height on the floor. Which one will rise to a greater height after striking the floor and why?

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Solution

(A) The ivory ball is more elastic than the wet-clay ball.
When the ivory ball strikes the floor,it undergoes elastic deformation and quickly regains its original shape,storing potential energy that helps it rebound.
In contrast,the wet-clay ball is highly plastic; it undergoes permanent deformation upon impact and absorbs most of the kinetic energy,resulting in little to no rebound.
Therefore,the ivory ball will rise to a greater height after striking the floor.

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Class 11 Questions

Class 11

Physics Questions

Chapter

Mechanical Properties of Solids

Subtopic

Basic of Elasticity, Stress and Strain relationship and Graphical analysis

Match the physical quantities in Column-$I$ with the details given in Column-$II$ appropriately:

Column-$I$ Column-$II$

$(a)$ $\text{Stress} \propto \text{Strain}$ $(i)$ $M^1 L^{-1} T^{-2}$

$(b)$ $\text{Dimensional formula for compressibility}$ $(ii)$ $M^{-1} L^1 T^2$

$(iii)$ $\text{Poisson's ratio}$

$(iv)$ $\text{Hooke's law}$

Column-$I$	Column-$II$
$(a)$ $\text{Stress} \propto \text{Strain}$	$(i)$ $M^1 L^{-1} T^{-2}$
$(b)$ $\text{Dimensional formula for compressibility}$	$(ii)$ $M^{-1} L^1 T^2$
	$(iii)$ $\text{Poisson's ratio}$
	$(iv)$ $\text{Hooke's law}$