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(A) The maximum velocity of a simple harmonic oscillator is given by the formula $v_{max} = A\omega$,where $A$ is the amplitude and $\omega$ is the an

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$v$

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(A) The maximum velocity of a simple harmonic oscillator is given by the formula $v_{max} = A\omega$,where $A$ is the amplitude and $\omega$ is the angular frequency.Since the two pendulums are identical,they have the same mass,length,and angular frequency $\omega$. It is given that they also have the same amplitude $A$.The phase difference between the two pendulums is constant at $\frac{\pi}{4}$,which implies that their frequencies are identical.Since $v_{max} = A\omega$ depends only on the amplitude and the angular frequency,and both parameters are identical for both pendulums,the maximum velocity of the second pendulum must also be $v$.

Two identical pendulums oscillate with a constant phase difference $\frac{\pi}{4}$ and same amplitude. If the maximum velocity of one is $v$,the maximum velocity of the other will be ........

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