Two identical conducting spheres $A$  and $B,$  carry equal charge. They are separated by a distance much larger than their diameter, and the force between them is $F$ . A third identical conducting sphere, $C,$  is uncharged. Sphere $C$  is first touched to $A,$ then to $B,$  and then removed. As a result, the force between $A$  and $B$  would be equal to

  • [JEE MAIN 2018]
  • A

    $\frac{{3F}}{4}$

  • B

    $\frac{{F}}{2}$

  • C

    $F$

  • D

    $\frac{{3F}}{8}$

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