Two gases A and B having the same volume,effu | vedclass

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(A) According to Graham's Law of Effusion,for gases of the same volume,the rate of effusion $r$ is inversely proportional to the square root of their

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$18$

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(A) According to Graham's Law of Effusion,for gases of the same volume,the rate of effusion $r$ is inversely proportional to the square root of their molar masses $M$ and inversely proportional to the time $t$ taken for effusion.$\frac{r_A}{r_B} = \frac{t_B}{t_A} = \sqrt{\frac{M_B}{M_A}}$Given:$t_A = 30 \ min$$t_B = 10 \ min$$M_A = 162$Substituting the values:$\frac{10}{30} = \sqrt{\frac{M_B}{162}}$$\frac{1}{3} = \sqrt{\frac{M_B}{162}}$Squaring both sides:$\frac{1}{9} = \frac{M_B}{162}$$M_B = \frac{162}{9} = 18$

Two gases $A$ and $B$ having the same volume,effuse through an orifice in $30 \ min$ and $10 \ min$ respectively. The molar mass of $A$ is $162$. The molar mass of $B$ will be

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