Two friends on roller-skates are standing $5\, m$ apart facing each other. One of them throws a ball of $2\, kg$ towards the other,who catches it. How will this activity affect the position of the two? Explain your answer.
(N/A) The separation between them will increase.
Initially,the momentum of both friends is zero as they are at rest.
According to the law of conservation of momentum,when the first person throws the ball,they must move in the opposite direction to the ball to conserve momentum.
When the second person catches the ball,they receive the momentum of the ball,which causes them to move backward in the direction of the ball's motion.
Consequently,both friends move away from each other,increasing the distance between them.
Initially,the momentum of both friends is zero as they are at rest.
According to the law of conservation of momentum,when the first person throws the ball,they must move in the opposite direction to the ball to conserve momentum.
When the second person catches the ball,they receive the momentum of the ball,which causes them to move backward in the direction of the ball's motion.
Consequently,both friends move away from each other,increasing the distance between them.
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