Two equal negative charges are fixed at the p | vedclass

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Question

The net force is given as,

$F_{n}=2 F \cos 	heta$

$=2 	imes \frac{1}{4 \pi \varepsilon_{0}}\left(\frac{-q Q}{a^{2}+x^{2}}ight) 	imes\left(\

Vedclass · Accepted Answer

execute oscillatory but not simple harmonic motion.

Vedclass · Answer

The net force is given as,

$F_{n}=2 F \cos 	heta$

$=2 	imes \frac{1}{4 \pi \varepsilon_{0}}\left(\frac{-q Q}{a^{2}+x^{2}}ight) 	imes\left(\frac{x}{\left(a^{2}+x^{2}ight)^{\frac{1}{2}}}ight)$

Thus, the restoring force is not linear, So, the motion will not be simple harmonic motion but the motion will be oscillatory.

Two equal negative charges are fixed at the points $ [0, a ]$ and $[0, -a]$ on the $y-$ axis. A positive charge $Q$ is released from rest at the points $[2a, 0]$ on the $x-$axis . The charge $Q$ will

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