Two equal bar magnets are kept as shown in the figure. The direction of the resultant magnetic field,indicated by the arrow head at the point $P$,is (approximately):

Two identical thin bar magnets are placed mutually at right angles such that the north pole of one touches the south pole of the other. The length of each bar magnet is $\ell$. The magnitude of the resultant magnetic moment of the system is $[m = \text{pole strength of the magnet}]$.

Three identical bar magnets are riveted together at the centre in the same plane as shown in the figure. This system is placed at rest in a slowly varying magnetic field. It is found that the system of magnets does not show any motion. The north-south poles of one magnet are shown in the figure. Determine the poles of the remaining two.

$A$ magnetized wire of magnetic moment $M$ and length $L$ is bent into an arc of a circle subtending an angle of $60^{\circ}$ at the center. The new magnetic moment is:

The average dipole moment of $Fe$ atoms is $1.8 \times 10^{-23} \ A-m^2$. The magnetic moment of an iron rod of length $10 \ cm$ and diameter $1 \ cm$ is........$A-m^2$: (density and atomic weight of $Fe$ are $7.87 \ g/cm^3$ and $55.87$ respectively).

The effective length of a magnet is $31.4 \, cm$ and its pole strength is $0.5 \, Am$. The magnetic moment,if it is bent in the form of a semicircle,will be.....$A m^2$.