Two ends of roads of length L and radius r of | vedclass

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Question

Heat flow rate $(\mathrm{Q})=\frac{\mathrm{KA} \Delta \mathrm{T}}{\Delta \mathrm{x}}$

$\mathrm{Q} \propto \frac{\mathrm{A}}{\Delta \mathrm{x}} \alp

Vedclass · Accepted Answer

$L = 100\,cm;\,\, r = 2\, cm$

Vedclass · Answer

Heat flow rate $(\mathrm{Q})=\frac{\mathrm{KA} \Delta \mathrm{T}}{\Delta \mathrm{x}}$

$\mathrm{Q} \propto \frac{\mathrm{A}}{\Delta \mathrm{x}} \alpha \frac{\pi \mathrm{r}^{2}}{\mathrm{L}}$

For maximum, by checking $\left(Q \propto \frac{r^{2}}{L}\right)$ for all

options, we can conclude : $\mathrm{L}=100 \mathrm{cm}: \mathrm{r}=2 \mathrm{cm}$

gives maximum value.

Two ends of roads of length $L$ and radius $r$ of the same material are kept at the same temperature which of the following rod conducts most heat?

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