Two elements,X and Y,have atomic numbers 33 a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $X$ with atomic number $33$ has the electronic configuration $[Ar] 3d^{10} 4s^2 4p^3$. It belongs to group $15$ and has a valency of $3$.$Y$ with

Vedclass · Accepted Answer

$XY_3$

Vedclass · Answer

(C) $X$ with atomic number $33$ has the electronic configuration $[Ar] 3d^{10} 4s^2 4p^3$. It belongs to group $15$ and has a valency of $3$.$Y$ with atomic number $17$ has the electronic configuration $[Ne] 3s^2 3p^5$. It belongs to group $17$ and has a valency of $1$.To form a stable compound,the valencies are crossed:$X^{3} Y^{1} \rightarrow XY_3$Therefore,the molecular formula of the stable compound formed between $X$ and $Y$ is $XY_3$. For example,if $X$ is $As$ $(Z=33)$ and $Y$ is $Cl$ $(Z=17)$,the compound is $AsCl_3$.

Two elements,$X$ and $Y$,have atomic numbers $33$ and $17$,respectively. The molecular formula of a stable compound formed between them is

Similar Questions

Calculate the mass percent of calcium,phosphorus,and oxygen in calcium phosphate $Ca_{3}(PO_{4})_{2}$.

The formula for calcium chlorite is

Calculate the molecular formula of an iron oxide,in which the mass percentages of iron and oxygen are $69.9$ and $30.1$,respectively.

The molecular formula of potash alum is

Provide information on the percentage proportion of elements and mixtures present in Portland cement.

Vedclass Test Series

Exam Paper Generator

Online Exam Module