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(B) According to Faraday's second law of electrolysis,when the same quantity of electricity is passed through different electrolytes connected in seri

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$58.5$

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(B) According to Faraday's second law of electrolysis,when the same quantity of electricity is passed through different electrolytes connected in series,the masses of the substances deposited are proportional to their equivalent masses.$\frac{	ext{Mass of } Ni}{	ext{Mass of } Al} = \frac{	ext{Equivalent mass of } Ni}{	ext{Equivalent mass of } Al}$Equivalent mass of $Ni = \frac{	ext{Atomic mass of } Ni}{	ext{Valency factor}} = \frac{58.5}{2} = 29.25 \ g/eq$Equivalent mass of $Al = \frac{	ext{Atomic mass of } Al}{	ext{Valency factor}} = \frac{27}{3} = 9 \ g/eq$Let the mass of $Ni$ be $w$.$\frac{w}{18} = \frac{29.25}{9}$$w = 18 	imes \frac{29.25}{9} = 2 	imes 29.25 = 58.5 \ g$Therefore,the weight of nickel obtained is $58.5 \ g$.

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