Two dice are thrown simultaneously,the probab | vedclass

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(C) When two dice are thrown simultaneously,the total number of possible outcomes is $6 	imes 6 = 36$. We are looking for the outcomes where the sum

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$ \frac{1}{9} $

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(C) When two dice are thrown simultaneously,the total number of possible outcomes is $6 	imes 6 = 36$. We are looking for the outcomes where the sum of the numbers on the two dice is $5$. The favorable outcomes are $(1, 4), (4, 1), (2, 3), (3, 2)$. There are $4$ such favorable outcomes. Therefore,the probability of obtaining a total score of $5$ is $P = \frac{	ext{Number of favorable outcomes}}{	ext{Total number of outcomes}} = \frac{4}{36} = \frac{1}{9}$.

List $I$	List $II$
$(A)$ Fleming's left hand rule	$(i)$ Direction of induced current
$(B)$ Right hand thumb rule	(ii) Magnitude and direction of magnetic induction
$(C)$ Biot-Savart law	(iii) Direction of force due to magnetic induction
$(D)$ Fleming's right hand rule	(iv) Direction of magnetic lines due to current

Two dice are thrown simultaneously,the probability of obtaining a total score of $5$ is

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