Two deuterons undergo nuclear fusion to form a Helium nucleus. Energy released in this process is ............. $MeV$ (given binding energy per nucleon for deuteron $= 1.1 \, MeV$ and for helium $= 7.0 \, MeV$)

$A$ nuclear fission process is given by $A^{240} \rightarrow B^{100} + C^{140} + Q$ (energy). If the binding energy per nucleon for nuclei $A, B,$ and $C$ are $7.6 \, MeV, 8.1 \, MeV,$ and $8.1 \, MeV$ respectively,then the energy $Q$ released is approximately $...... \, MeV$.

The nucleus $_{92}U^{234}$ splits exactly in half in a fission reaction in which two neutrons are released. The resultant nuclei are

If the energy released in the fission of one nucleus is $200 \, MeV$, then the number of nuclei required per second in a power plant of $16 \, kW$ will be:

In the fusion reaction,${ }_1 H^2+{ }_1 H^2 \rightarrow{ }_2 He^4+Q$,where $Q$ is the energy released. If $c$ is the speed of light and $m$ is the mass of each deuterium nucleus,then the mass of the helium nucleus formed is:

Light energy emitted by stars is due to