Two compounds I and II are eluted by column c | vedclass

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(B) In column chromatography,the compound that is more strongly adsorbed on the stationary phase moves slower through the column. Given that the adsor

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$II$ moves faster and has higher $R_f$ value than $I$

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(B) In column chromatography,the compound that is more strongly adsorbed on the stationary phase moves slower through the column. Given that the adsorption of $I > II$,compound $I$ is more strongly adsorbed than compound $II$. Therefore,compound $I$ moves slower and travels a shorter distance,while compound $II$ moves faster and travels a longer distance. The $R_f$ value is defined as the ratio of the distance traveled by the substance to the distance traveled by the solvent front. Since compound $II$ travels a greater distance,it has a higher $R_f$ value than compound $I$.

List-$I$	List-$II$
$A$. Physisorption	$I$. Single layer adsorption
$B$. Chemisorption	$II$. $20-40 \, kJ \, mol^{-1}$
$C$. $N_{2(g)} + 3H_{2(g)} \xrightarrow{Fe(s)} 2NH_{3(g)}$	$III$. Chromatography
$D$. Analytical Application of Adsorption	$IV$. Heterogeneous catalysis

Two compounds $I$ and $II$ are eluted by column chromatography (adsorption of $I > II$). Which one of the following is a correct statement?

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