Two coils A and B are wound on the same iron | vedclass

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Question

(B) When two coils are wound on the same iron core,the magnetic flux $\phi$ passing through each turn of both coils is the same because the iron core

Vedclass · Accepted Answer

The magnetic flux linked are in the ratio $\frac{\phi_A}{\phi_B} = \frac{N_A}{N_B}$.

Vedclass · Answer

(B) When two coils are wound on the same iron core,the magnetic flux $\phi$ passing through each turn of both coils is the same because the iron core provides a path of high permeability for the magnetic field lines.However,the total magnetic flux linkage for a coil with $N$ turns is given by $\lambda = N\phi$.For coil $A$,the flux linkage is $\lambda_A = N_A \phi$.For coil $B$,the flux linkage is $\lambda_B = N_B \phi$.The ratio of the flux linkages is $\frac{\lambda_A}{\lambda_B} = \frac{N_A \phi}{N_B \phi} = \frac{N_A}{N_B}$.According to Faraday's law of induction,the induced emf $E$ is given by $E = -\frac{d\lambda}{dt} = -N \frac{d\phi}{dt}$.Therefore,the ratio of induced emf is $\frac{E_A}{E_B} = \frac{N_A (d\phi/dt)}{N_B (d\phi/dt)} = \frac{N_A}{N_B}$.Comparing this with the given options,option $(b)$ correctly describes the relationship between the flux linkages (often referred to as the magnetic flux linked with the coils).

Two coils $A$ and $B$ are wound on the same iron core as shown in the figure. The number of turns in the coils $A$ and $B$ are $N_A$ and $N_B$ respectively. Identify the correct statement.

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