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(C) The magnetic moment $\vec{M}$ of a current loop is given by $\vec{M} = I\vec{A}$,where $I$ is the current and $\vec{A}$ is the area vector.From th

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$+ 1.1\,\hat{k}\,A\cdot m^2$

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(C) The magnetic moment $\vec{M}$ of a current loop is given by $\vec{M} = I\vec{A}$,where $I$ is the current and $\vec{A}$ is the area vector.From the figure,the current in the outer loop $(r_2 = 0.3\,m)$ is in the counter-clockwise direction,so its magnetic moment is $\vec{M}_2 = I(\pi r_2^2)\hat{k}$.The current in the inner loop $(r_1 = 0.2\,m)$ is in the clockwise direction,so its magnetic moment is $\vec{M}_1 = -I(\pi r_1^2)\hat{k}$.The net magnetic moment is $\vec{M} = \vec{M}_2 + \vec{M}_1 = I\pi(r_2^2 - r_1^2)\hat{k}$.Substituting the values: $I = 7\,A$,$r_2 = 0.3\,m$,$r_1 = 0.2\,m$.$\vec{M} = 7 	imes \pi 	imes (0.3^2 - 0.2^2)\hat{k}$$\vec{M} = 7 	imes \frac{22}{7} 	imes (0.09 - 0.04)\hat{k}$$\vec{M} = 22 	imes 0.05\hat{k} = 1.1\,\hat{k}\,A\cdot m^2$.

Two circular concentric loops of radii $r_1 = 20\,cm$ and $r_2 = 30\,cm$ are placed in the $X, Y-$ plane as shown in the figure. $A$ current $I = 7\,A$ is flowing through them in opposite directions. The magnetic moment of this loop system is

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