Two children are at opposite ends of an alumi | vedclass

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(A) Let the length of the aluminium rod be $x$.Let $v_1$ be the speed of sound in air $(346 \ m/s)$ and $v_2$ be the speed of sound in aluminium $(642

Vedclass · Accepted Answer

$t_1:t_2 = 18.55:1$

Vedclass · Answer

(A) Let the length of the aluminium rod be $x$.Let $v_1$ be the speed of sound in air $(346 \ m/s)$ and $v_2$ be the speed of sound in aluminium $(6420 \ m/s)$.The time taken by sound to travel through air is $t_1 = x / v_1$.The time taken by sound to travel through the aluminium rod is $t_2 = x / v_2$.The ratio of the times is $t_1 / t_2 = (x / v_1) / (x / v_2) = v_2 / v_1$.Substituting the values: $t_1 / t_2 = 6420 / 346 \approx 18.55$.Therefore,the ratio $t_1:t_2$ is $18.55:1$.

Two children are at opposite ends of an aluminium rod. One strikes the end of the rod with a stone. Find the ratio of times taken by the sound wave in air and in aluminium to reach the second child.

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