(B) The dipole moment $p$ is given by $p = q \times d$.Given $q = 0.01\,C$ and $d = 0.4\,mm = 0.4 \times 10^{-3}\,m$.$p = 0.01 \times 0.4 \times 10^{-

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(B) The dipole moment $p$ is given by $p = q \times d$.Given $q = 0.01\,C$ and $d = 0.4\,mm = 0.4 \times 10^{-3}\,m$.$p = 0.01 \times 0.4 \times 10^{-3} = 4 \times 10^{-6}\,Cm$.The electric field $E = 10\,dyne/C$. Since $1\,dyne = 10^{-5}\,N$,$E = 10 \times 10^{-5}\,N/C = 10^{-4}\,N/C$.The torque $\tau$ is given by $\tau = pE \sin \theta$,where $\theta = 30^{\circ}$.$\tau = (4 \times 10^{-6}) \times (10^{-4}) \times \sin 30^{\circ}$.$\tau = 4 \times 10^{-10} \times 0.5 = 2.0 \times 10^{-10}\,Nm$.

Class 12 Physics Electric Charges and Fields Electric Dipole and Electric Field

Easy

Two charges each of magnitude $0.01\,C$ and separated by a distance of $0.4\,mm$ constitute an electric dipole. If the dipole is placed in a uniform electric field $\vec{E}$ of $10\,dyne/C$ making a $30^{\circ}$ angle with $\vec{E}$,the magnitude of torque acting on the dipole is:

JEE MAIN 2023 All JEE MAIN

A
$4.0 \times 10^{-10}\,Nm$
B
$2.0 \times 10^{-10}\,Nm$
C
$1.0 \times 10^{-8}\,Nm$
D
$1.5 \times 10^{-9}\,Nm$

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Electric Charges and Fields

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Electric Dipole and Electric Field

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Two charges each of magnitude $0.01\,C$ and separated by a distance of $0.4\,mm$ constitute an electric dipole. If the dipole is placed in a uniform electric field $\vec{E}$ of $10\,dyne/C$ making a $30^{\circ}$ angle with $\vec{E}$,the magnitude of torque acting on the dipole is:

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The electric field at point $A$ due to an electric dipole with dipole moment $p$ is perpendicular to the dipole moment vector $p$. The angle $\theta$ is:

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