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(C) Let the distance between the charges $+q$ and $-q$ be $2r$. The midpoint $O$ is at a distance $r$ from each charge.$1$. Electric Potential $(V)$:

Vedclass · Accepted Answer

Electric field is not zero but potential is zero

Vedclass · Answer

(C) Let the distance between the charges $+q$ and $-q$ be $2r$. The midpoint $O$ is at a distance $r$ from each charge.$1$. Electric Potential $(V)$: The potential at point $O$ is the algebraic sum of potentials due to both charges.$V = V_+ + V_- = \frac{kq}{r} + \frac{k(-q)}{r} = 0$.$2$. Electric Field $(E)$: The electric field due to $+q$ at $O$ is directed away from $+q$ (towards the right),and the electric field due to $-q$ at $O$ is directed towards $-q$ (also towards the right).Since both fields are in the same direction,they add up:$E = E_+ + E_- = \frac{kq}{r^2} + \frac{kq}{r^2} = \frac{2kq}{r^2} 
eq 0$.Therefore,the electric field is not zero,but the potential is zero.

Two charges $+q$ and $-q$ are situated at a certain distance. At the point exactly midway between them:

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