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(A) Mass of both cars,$m_1 = m_2 = 1000 \ kg$.Initial velocity of the first car,$u_1 = 5 \ m s^{-1}$.Initial velocity of the second car,$u_2 = -5 \ m

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(A) Mass of both cars,$m_1 = m_2 = 1000 \ kg$.Initial velocity of the first car,$u_1 = 5 \ m s^{-1}$.Initial velocity of the second car,$u_2 = -5 \ m s^{-1}$ (since they are moving in opposite directions).Let $v$ be the common velocity of the combined cars after the collision.According to the law of conservation of momentum,the total momentum before the collision is equal to the total momentum after the collision.$m_1 u_1 + m_2 u_2 = (m_1 + m_2) v$Substituting the values:$1000 	imes 5 + 1000 	imes (-5) = (1000 + 1000) v$$5000 - 5000 = 2000 v$$0 = 2000 v$$v = 0 \ m s^{-1}$.Therefore,the combined cars will come to rest after the collision.

Two cars each of mass $1000 \ kg$ are moving in a straight line but in opposite directions. The velocity of each car is $5 \ m s^{-1}$ before the collision during which they stick together. What will be the velocity of the combined cars after collision (in $m s^{-1}$)?

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