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(D) Let the speed of the third car be $v \, km/h$.Since the third car is moving in the opposite direction to the first two cars,the relative velocity

Vedclass · Accepted Answer

$45$

Vedclass · Answer

(D) Let the speed of the third car be $v \, km/h$.Since the third car is moving in the opposite direction to the first two cars,the relative velocity of the third car with respect to the other two cars is $(v + 30) \, km/h$.The distance between the two cars is $5 \, km$.The time interval between meeting the two cars is $4 \, minutes = \frac{4}{60} \, hours = \frac{1}{15} \, hours$.Using the formula for relative motion: $d = v_{	ext{rel}} 	imes t$$5 \, km = (v + 30) \, km/h 	imes \frac{1}{15} \, h$$v + 30 = 5 	imes 15$$v + 30 = 75$$v = 75 - 30 = 45 \, km/h$.Therefore,the speed of the third car is $45 \, km/h$.

Two cars are moving in the same direction with a speed of $30 \, km/h$. They are separated from each other by $5 \, km$. $A$ third car moving in the opposite direction meets the two cars after an interval of $4 \, minutes$. The speed of the third car is .......... $km/h$.

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