Two cards are drawn successively with replace | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Total number of cards $= 52$. Total number of queens $= 4$. Probability of getting a queen in one draw,$p = \frac{4}{52} = \frac{1}{13}$. Probabil

Vedclass · Accepted Answer

$\frac{2}{13}$

Vedclass · Answer

(C) Total number of cards $= 52$. Total number of queens $= 4$. Probability of getting a queen in one draw,$p = \frac{4}{52} = \frac{1}{13}$. Probability of not getting a queen,$q = 1 - p = \frac{12}{13}$. Since the cards are drawn with replacement,this follows a binomial distribution $B(n, p)$ with $n = 2$ and $p = \frac{1}{13}$. The mean of a binomial distribution is given by $E(X) = np$. $E(X) = 2 	imes \frac{1}{13} = \frac{2}{13}$.

Two cards are drawn successively with replacement from a well-shuffled pack of $52$ cards. The mean of the number of queens is:

Similar Questions

For a binomial variate $X$ with $n=6$,if $P(X=4)=\frac{135}{2^{12}}$,then its variance is

Suppose $X$ follows a binomial distribution with parameters $n$ and $p$,where $0 < p < 1$. If $\frac{P(X=r)}{P(X=n-r)}$ is independent of $n$ for every $r$,then $p$ is equal to

The mean and variance of a binomial distribution are $5$ and $4$ respectively. Then what is $P(X=1)$?

$A$ die is tossed thrice. If the event of getting an even number is a success,then the probability of getting at least $2$ successes is

$A$ die is thrown thrice. If getting $1$ or $6$ in a single throw is considered as success,then the variance of the number of successes is

Vedclass Test Series

Exam Paper Generator

Online Exam Module