Two capillary tubes of same length each of $50 \ cm$ but of different radii $4 \ mm$ and $2 \ mm$ are connected in series. When water flows,the pressure difference between the ends of the arrangement is $P$. Then the pressure difference between the ends of the first tube is

  • A
    $\frac{P}{2}$
  • B
    $\frac{P}{17}$
  • C
    $\frac{P}{4}$
  • D
    $\frac{P}{8}$

Explore More

Similar Questions

What is critical speed in the context of fluid flow?

$A$ liquid is flowing in a horizontal uniform capillary tube under a constant pressure difference $P$. The value of pressure for which the rate of flow of the liquid is doubled when the radius and length both are doubled is

Range of Reynolds number are given in Column - $I$ and types of flow are given in Column - $II$. Match them appropriately.
Column - $I$ Column - $II$
$(a)$ $R_e > 2000$ $(i)$ Streamline
$(b)$ $1000 < R_e < 2000$ $(ii)$ Turbulent
$(iii)$ Unsteady

In Poiseuille's method for the determination of the coefficient of viscosity,the physical quantity that requires the greatest accuracy in measurement is:

Show that the Reynolds number is dimensionless.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo