Two capillary tubes of different diameters are dipped in water. The rise of water is

When a capillary is dipped in water,water rises $0.015 \ m$ in it. If the surface tension of water is $75 \times 10^{-3} \ N/m$,the radius of the capillary is ....... $mm$.

$A$ capillary tube of radius $R$ is immersed in water and water rises in it to a height $H$. The mass of water in the capillary tube is $M$. If the radius of the tube is halved,the mass of water that will rise in the capillary tube will now be

Water rises up to a height $h$ in a capillary tube of a certain diameter. This capillary tube is replaced by a similar tube of half the diameter. Now,the water will rise to a height of:

Water rises up to a height $h$ in a capillary tube immersed vertically in water. When this whole arrangement is taken to a depth $d$ in a mine,the water level rises up to a height $h^{\prime}$. If $R$ is the radius of the earth,then the ratio $\frac{h}{h^{\prime}}$ is

In a surface tension experiment with a capillary tube,water rises up to $0.1\, m$. If the same experiment is repeated on an artificial satellite,which is revolving around the Earth,water will rise in the capillary tube up to a height of: