Two capacitors of 100 mu F and 50 mu F are co | vedclass

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(D) When two capacitors are connected in parallel,the total charge $Q_{total}$ is the sum of the individual charges,and the total capacitance $C_{eq}$

Vedclass · Accepted Answer

$\frac{80}{3} 	ext{ V}$

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(D) When two capacitors are connected in parallel,the total charge $Q_{total}$ is the sum of the individual charges,and the total capacitance $C_{eq}$ is the sum of the individual capacitances.Given: $C_1 = 100 \mu F$,$V_1 = 20 	ext{ V}$,$C_2 = 50 \mu F$,$V_2 = 40 	ext{ V}$.Charge on the first capacitor: $Q_1 = C_1 V_1 = 100 \mu F 	imes 20 	ext{ V} = 2000 \mu C$.Charge on the second capacitor: $Q_2 = C_2 V_2 = 50 \mu F 	imes 40 	ext{ V} = 2000 \mu C$.Total charge: $Q_{total} = Q_1 + Q_2 = 2000 \mu C + 2000 \mu C = 4000 \mu C$.Equivalent capacitance: $C_{eq} = C_1 + C_2 = 100 \mu F + 50 \mu F = 150 \mu F$.The common potential $V$ is given by $V = \frac{Q_{total}}{C_{eq}}$.$V = \frac{4000 \mu C}{150 \mu F} = \frac{400}{15} 	ext{ V} = \frac{80}{3} 	ext{ V}$.

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