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(D) Let the time taken for the buses to meet be $t$ hours.Distance travelled by the first bus is $d_1 = 20t$.Distance travelled by the second bus is $

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$720$

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(D) Let the time taken for the buses to meet be $t$ hours.Distance travelled by the first bus is $d_1 = 20t$.Distance travelled by the second bus is $d_2 = 25t$.According to the problem,the second bus has travelled $80 \, km$ more than the first bus:$d_2 - d_1 = 80$$25t - 20t = 80$$5t = 80$$t = 16 \, 	ext{hours}$.The total distance between the two bus stations is the sum of the distances travelled by both buses:$	ext{Total Distance} = d_1 + d_2 = 20t + 25t = 45t$.Substituting $t = 16$:$	ext{Total Distance} = 45 	imes 16 = 720 \, km$.

Two buses start at the same time from two bus stations and proceed towards each other at the rates of $20 \, km/h$ and $25 \, km/h$ respectively. When they meet,one bus has travelled $80 \, km$ more than the other. Find the distance between the two bus stations (in $km$).

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