Two bodies of mass m_1 and m_2 (m_2 m_1) ar | vedclass

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(C) The system consists of two masses $m_1$ and $m_2$ connected by a string over a pulley. Since $m_2 > m_1$,the mass $m_2$ tends to move downwards du

Vedclass · Accepted Answer

$(m_2 - m_1)gv$

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(C) The system consists of two masses $m_1$ and $m_2$ connected by a string over a pulley. Since $m_2 > m_1$,the mass $m_2$ tends to move downwards due to gravity,which pulls $m_1$ upwards. To pull $m_1$ upwards with a constant velocity $v$,an external force $F_{ext}$ must be applied. For the system to move with constant velocity,the net force on the system must be zero. The forces acting on the system are the gravitational force on $m_2$ ($m_2g$ downwards),the gravitational force on $m_1$ ($m_1g$ downwards),and the external force $F_{ext}$ acting on $m_1$ (downwards). Equating the forces for equilibrium: $F_{ext} + m_1g = m_2g$. Thus,$F_{ext} = (m_2 - m_1)g$. The instantaneous power $P$ delivered by the external agent is given by $P = F_{ext} \cdot v$. Substituting the value of $F_{ext}$,we get $P = (m_2 - m_1)gv$.

Two bodies of mass $m_1$ and $m_2$ $(m_2 > m_1)$ are connected by a light inextensible string which passes through a smooth fixed pulley. The instantaneous power delivered by an external agent to pull $m_1$ with constant velocity $v$ is

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