Two bodies $P$ and $Q$ have thermal emissivities of $\varepsilon_P$ and $\varepsilon_Q$ respectively. Surface areas of these bodies are same and the total radiant power is also emitted at the same rate. If temperature of $P$ is $\theta_P$ kelvin then temperature of $Q$ i.e. $\theta_Q$ is
Two bodies $P$ and $Q$ have thermal emissivities of $\varepsilon_P$ and $\varepsilon_Q$ respectively. Surface areas of these bodies are same and the total radiant power is also emitted at the same rate. If temperature of $P$ is $\theta_P$ kelvin then temperature of $Q$ i.e. $\theta_Q$ is
- A
${\left( {\frac{{{\varepsilon _Q}}}{{{\varepsilon _P}}}} \right)^{1/4}}\,{\theta _P}\,$
- B
${\left( {\frac{{{\varepsilon _P}}}{{{\varepsilon _Q}}}} \right)^{1/4}}\,{\theta _P}\,$
- C
${\left( {\frac{{{\varepsilon _Q}}}{{{\varepsilon _P}}}} \right)^{1/4}}\,\, \times \,\frac{1}{{{\theta _P}\,}}$
- D
${\left( {\frac{{{\varepsilon _Q}}}{{{\varepsilon _P}}}} \right)^4}\,\,{\theta _P}$
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