(B) The tension $T$ in the wire for a system of two masses $m$ and $M$ connected by a string over a pulley is given by the formula: $T = \frac{2mM}{m

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(B) The tension $T$ in the wire for a system of two masses $m$ and $M$ connected by a string over a pulley is given by the formula: $T = \frac{2mM}{m + M}g$.Stress is defined as the force per unit area. In this case,the force is the tension $T$ in the wire.$\text{Stress} = \frac{T}{A} = \frac{2mM}{A(m + M)}g$.Given that $M = 2m$,we substitute this value into the expression:$\text{Stress} = \frac{2m(2m)}{A(m + 2m)}g$$\text{Stress} = \frac{4m^2}{A(3m)}g$$\text{Stress} = \frac{4mg}{3A}$.

Class 11 Physics Newton's Laws of Motion and Friction Tension Force and Pulley Block System

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Two blocks of masses $m$ and $M$ are connected by means of a metal wire of cross-sectional area $A$ passing over a frictionless fixed pulley as shown in the figure. The system is then released. If $M = 2m$,then the stress produced in the wire is

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A
$\frac{2mg}{3A}$
B
$\frac{4mg}{3A}$
C
$\frac{mg}{A}$
D
$\frac{3mg}{4A}$

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Class 11

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Newton's Laws of Motion and Friction

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Tension Force and Pulley Block System

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Two blocks of masses $m$ and $M$ are connected by means of a metal wire of cross-sectional area $A$ passing over a frictionless fixed pulley as shown in the figure. The system is then released. If $M = 2m$,then the stress produced in the wire is

Similar Questions

$A$ lift is going up. The total mass of the lift and the passenger is $1500\, kg$. The variation in the speed of the lift is as given in the graph. The tension in the rope pulling the lift at $t = 11\, s$ will be ............ $N$.

Two masses of $1\, kg$ and $5\, kg$ are attached to the ends of a massless string passing over a pulley of negligible weight. The pulley itself is attached to a light spring balance as shown in the figure. When the masses are released and start moving,the reading of the spring balance will be:

Three identical blocks of masses $m = 2\; kg$ are pulled by a force $F = 10.2\; N$ with an acceleration of $0.6\; m/s^2$ on a frictionless surface. What is the tension (in $N$) in the string between the blocks $B$ and $C$?

$A$ body of weight $200 \,N$ is suspended from a tree branch through a chain of mass $10 \,kg$. The branch pulls the chain by a force equal to (if $g=10 \,m/s^2$): (in $\,N$)

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