Two beams of red and violet colours are made | vedclass

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(A) In a prism,the angle of the prism $A$ is given by the sum of the angles of refraction at the two faces: $A = r_1 + r_2$.At the position of minimum

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$30^{\circ}$ for both the colours

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(A) In a prism,the angle of the prism $A$ is given by the sum of the angles of refraction at the two faces: $A = r_1 + r_2$.At the position of minimum deviation,the light ray passes symmetrically through the prism,which implies that the angle of incidence equals the angle of emergence $(i = e)$.Consequently,the angles of refraction at both faces are equal: $r_1 = r_2 = r$.Substituting this into the prism formula: $A = r + r = 2r$.Therefore,$r = A / 2$.Given the prism angle $A = 60^{\circ}$,the angle of refraction for both colours is $r = 60^{\circ} / 2 = 30^{\circ}$.Thus,the angle of refraction is $30^{\circ}$ for both the red and violet colours.

Two beams of red and violet colours are made to pass separately through a prism (angle of the prism is $60^{\circ}$). In the position of minimum deviation,the angle of refraction will be

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